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60x^2-69x+18=0
a = 60; b = -69; c = +18;
Δ = b2-4ac
Δ = -692-4·60·18
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-21}{2*60}=\frac{48}{120} =2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+21}{2*60}=\frac{90}{120} =3/4 $
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